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If the areas of three adjacent faces of a cuboid are x, y, z square units, respectively, then the volume of the cuboid is:
Question

If the areas of three adjacent faces of a cuboid are x, y, z square units, respectively, then the volume of the cuboid is:

A.

xyz \sqrt{xyz}​ cubic units

B.

xyz cubic units

C.

xyz2 \sqrt{\frac{xyz}2}​ cubic units

D.

xyz3\sqrt[3]{xyz}​ cubic units

Correct option is A

Given
Areas of adjacent faces of the cuboid = x, y, z
Formula Used
Volume of cuboid (V) = length × breadth × height
Solution
Let length, breadth, and height of the cuboid be l, b, and h respectively.
x = l × b
y = b × h
z = h × l
Multiply all three equations together:
x × y × z = (l × b) × (b × h) × (h × l)
xyz=l2b2h2xyz=(lbh)2xyz = l^2 b^2 h^2 \\xyz = (lbh)^2​​
Since V = lbh, we substitute V:
xyz = V2V^2​​
V = xyz \sqrt{xyz}​​
Final Answer
So the correct answer is (a)

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