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    If the areas of three adjacent faces of a cuboid are x, y, z square units, respectively, then the volume of the cuboid is:
    Question

    If the areas of three adjacent faces of a cuboid are x, y, z square units, respectively, then the volume of the cuboid is:

    A.

    xyz \sqrt{xyz}​ cubic units

    B.

    xyz cubic units

    C.

    xyz2 \sqrt{\frac{xyz}2}​ cubic units

    D.

    xyz3\sqrt[3]{xyz}​ cubic units

    Correct option is A

    Given
    Areas of adjacent faces of the cuboid = x, y, z
    Formula Used
    Volume of cuboid (V) = length × breadth × height
    Solution
    Let length, breadth, and height of the cuboid be l, b, and h respectively.
    x = l × b
    y = b × h
    z = h × l
    Multiply all three equations together:
    x × y × z = (l × b) × (b × h) × (h × l)
    xyz=l2b2h2xyz=(lbh)2xyz = l^2 b^2 h^2 \\xyz = (lbh)^2​​
    Since V = lbh, we substitute V:
    xyz = V2V^2​​
    V = xyz \sqrt{xyz}​​
    Final Answer
    So the correct answer is (a)

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