A cuboid with dimensions (8×2×4) meters is melted and recast into a cube.
Find the total surface area of the cube.

Correct option is C

Given
Dimensions of the cuboid = $$8m \times 2 m \times 4 m$$​​

Formula Used
Volume of cuboid = $$l \times b \times h$$​​
Volume of cube = $$a^3($$​where a is the edge length)
Total Surface Area of cube = $$6a^2$$​​

Solution
Volume of the cuboid = $$8 \times 2 \times 4 = 64 m^3$$​​
Since the cuboid is melted to form a cube, their volumes are equal.
Volume of cube = $$a^3 = 64$$​​
​$$a = \sqrt[3]{64} = 4 m$$​​
Now, calculate the Total Surface Area (TSA) of the cube:
TSA =  $$6 \times (4)^2$$​​
TSA = $$6 \times 16 = 96 m^2$$​​
Final Answer
So the correct answer is (c)