A triangle ABC with sides 3 cm, 4 cm and 5 cm is revolved about the side 3 cm. Find the volume of the solid so obtained. (Use π = 3.14)

Correct option is D

Given
Triangle sides = 3 cm, 4 cm, 5 cm
Revolved about the side 3 cm
​$$\pi = 3.14$$​​
Formula Used
Volume of a cone = $$\frac{1}{3} \times \pi \times r^2 \times h$$​​
Solution
Revolving a right-angled triangle about its altitude forms a cone.
Height of the cone, h = 3 cm
Radius of the base, r = 4 cm
Volume = $$\frac{1}{3} \times 3.14 \times 4^2 \times 3$$​​
Volume = $$3.14 \times 16 = 50.24\, \text{cubic cm}$$​
Final Answer
So the correct answer is (d) 

Exam Hall Method: