The value of the integral ∫0∞e−x2 dx\int_0^{\infty} e^{-x^2} \, dx∫0∞e−x2dx is
What is wrong with the following calculation?
∫−131x2dx=−43\int_{-1}^3 \frac{1}{x^2} d x=-\frac{4}{3}∫−13x21dx=−34
∫0π4sin3θ dθ= ?\int_{0}^{\frac{\pi}{4}} \sin^3 \theta \, d\theta = \, ?∫04πsin3θdθ=?
Let 3f(x)+f(1x)=1x+1\begin{aligned}3f(x) + f\left(\frac{1}{x}\right) = \frac{1}{x} + 1\end{aligned}3f(x)+f(x1)=x1+1 Then what is 8∫12f(x) dx8 \int_{1}^{2} f(x) \, dx8∫12f(x)dx equal to?
Suggested Test Series