The highest common factor of 363, 495, and 561 is N. The digit sum of N is:
Given:
The numbers are 363, 495, and 561.
Solution:
Prime factorization of 363:
363 = 3 × 121 = 3 × 11 × 11
Prime factorization of 495:
495 = 5 × 99 = 5 × 3 × 33 = 5 × 3 × 3 × 11
Prime factorization of 561:
561 = 3 × 187 = 3 × 11 × 17
The common prime factors are 3 and 11.
HCF = 3 × 11 = 33
Digit sum of 33 = 3 + 3 = 6
The digit sum of N is 6.
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