The greatest number, which divides 2340 and 1551 to leave 40 and 33 respectively as remainders, is:

Correct option is D

Given:
Number 1 = 2340, Remainder = 40
Number 2 = 1551, Remainder = 33
Formula Used:
Required number = HCF of (2340 − 40) and (1551 − 33)
Solution:
=> (2340 − 40) = 2300
=> (1551 − 33) = 1518
Required number = HCF of 2300 and 1518
Prime factorization:
2300 = 2 × 2 × 5 × 5 × 23 = 2² × 52 × 23
1518 = 2 × 3 × 11 × 23
=> HCF = 2 × 23 = 46
∴ The greatest number = 46.