The greatest number that divides 210, 1245 and 2160 is:
Given:
Numbers: 210, 1245, 2160
Formula Used:
HCF = Product of all common prime factors with the smallest powers
Solution:
210 = 2 × 3 × 5 × 7
1245 = 3 × 5 × 83
2160 = 2⁴ × 3³ × 5
HCF = 3 × 5 = 15
The greatest number that divides 210, 1245, and 2160 is 15.
English
80 Questions
160 Marks
60 Mins English English20 Questions40 Marks25 Mins English English25 Questions50 Marks15 Mins EnglishFind the HCF of the numbers 2520, 3600, 5880.
The number of pairs of positive integers whose sum is 99 and HCF is 9 is
Find the HCF of 2.8, 11.2 and 0.84 .
Find the Highest Common Factor (HCF) of 372, 732 and 2196.
If the HCF of the expressions (x + 3) (2x² – 3x + a) and (x – 2) (3x² + 10x – b) is x² + x – 6, then what is the value of (2a – 3b) ?
The greatest number, which divides 1938 and 2337 to leave 0 and 3 respectively as remainders, is:
The greatest number, which divides 711 and 1040 to leave 48 and 20 respectively as remainders, is:
The greatest number that divides 210, 1245 and 2160 is:
There are four equilateral triangles with sides 95 cm, 76 cm, 57 cm and 152 cm. What maximum size scale (in cm) can measure all of them exactly?
The greatest number, which divides 2340 and 1551 to leave 40 and 33 respectively as remainders, is:
Suggested Test Series
Suggested Test Series
Find the HCF of the numbers 2520, 3600, 5880.
The number of pairs of positive integers whose sum is 99 and HCF is 9 is
Find the HCF of 2.8, 11.2 and 0.84 .
Find the Highest Common Factor (HCF) of 372, 732 and 2196.
If the HCF of the expressions (x + 3) (2x² – 3x + a) and (x – 2) (3x² + 10x – b) is x² + x – 6, then what is the value of (2a – 3b) ?
The greatest number, which divides 1938 and 2337 to leave 0 and 3 respectively as remainders, is:
The greatest number, which divides 711 and 1040 to leave 48 and 20 respectively as remainders, is:
The greatest number that divides 210, 1245 and 2160 is:
There are four equilateral triangles with sides 95 cm, 76 cm, 57 cm and 152 cm. What maximum size scale (in cm) can measure all of them exactly?
The greatest number, which divides 2340 and 1551 to leave 40 and 33 respectively as remainders, is:
