The greatest number, which divides 1938 and 2337 to leave 0 and 3 respectively as remainders, is:
Given:
First number = 1938, remainder = 0
Second number = 2337, remainder = 3
Formula Used:
If a number leaves remainders r₁ and r₂,
Required number = HCF of (given numbers − respective remainders)
Solution:
1938 − 0 = 1938
2337 − 3 = 2334
HCF of 1938 and 2334 = 6
English
80 Questions
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60 Mins English English20 Questions40 Marks12 Mins English English80 Questions160 Marks60 Mins EnglishFind the Highest Common Factor (HCF) of 372, 732 and 2196.
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