Find the HCF of 2.8, 11.2 and 0.84 .

Correct option is B

Given:
Numbers: 2.8, 11.2, 0.84
Solution:
Make the number of decimal places equal for all values:
2.80, 11.20, 0.84
Consider these as integers without decimals:
280, 1120, 84
Find the HCF of 280, 1120, and 84 by prime factorization:
280 = $$2^3 × 5 × 7$$​​
1120 = $$2^5 × 5 × 7$$​​
84 = $$2^2 × 3 × 7$$​​
The common prime factors with the lowest power are 2^2 and 7.
HCF of integers = $$2^2 × 7$$​ = 4 × 7 = 28
Since the original numbers have two decimal places, apply two decimal places to the integer HCF:
HCF $$= \frac{28}{100}$$​ = 0.28
Final Answer
So the correct answer is (b)