The current across the 3 ohm resistance in the given circuit is:

Correct option is A

The correct answer to the problem is A) 5/7 A.

Explanation:

• The given circuit has two resistors of  3Ω and 4 Ω, connected in series. The total resistance of the circuit is the sum of the individual resistances:

R_total=R1+R2=3+4=7 Ω

• If we assume a voltage V is applied across the circuit, the total current in the circuit is:

​$$Itotal=\frac{V}{R_{\text{total}}} = \frac{V}{7} \, \text{A}$$​​

• The current through resistors in a series circuit is the same. Therefore, the current across the 3 Ω3 \, \Omega3Ω resistor is also:

​$$I3 ohm=\frac{V}{7} \, \text{A}$$​​

• If V=5V = 5V=5 volts (assuming a supply voltage of 5V for this question), the current across the 3 Ω3 \, \Omega3Ω resistor is:

​$$I3 ohm=\frac{5}{7} \, \text{A}$$​​

Key Facts (Exam-Oriented):

•  The current is the same in all components of a series circuit.
• Total resistance in series circuits is the sum of individual resistances.
• Ohm's Law is applied:$$I= \frac{V}{R}$$​​
• Current across any series element is calculated using the total circuit resistance