A resistor having 3 Ω resistance is connected to a 3 V battery and an ammeter. Considering the ammeter as a galvanometer having resistance 60 Ω with a shunt having 0.02 Ω, the current in the circuit would be

Correct option is A

Correct answer is A
Calculation:
The galvanometer and the shunt are connected in parallel. The equivalent resistance of this combination is calculated as:
Req = (Rg × Rs) / (Rg + Rs)
Req = (60 × 0.02) / (60 + 0.02) ⇒ Req = 1.2 / 60.02 ⇒ Req ≈ 0.02 Ω
The total resistance in the circuit is the sum of the resistor and the equivalent resistance of the galvanometer-shunt combination:
Rtotal = R + Req
Rtotal = 3 + 0.02 ⇒ Rtotal = 3.02 Ω
Using Ohm's Law (I = V/R), the current in the circuit is:
I = V / Rtotal
I = 3 / 3.02 ⇒ I ≈ 0.993 A