The average of the squares of the first 82 natural numbers is

Correct option is D

Given:
n = 82
Formula Used:
Average of squares of first n natural numbers = $$\frac{(n+1)(2n+1)}{6}$$​​
Solution:
​$$Average = \frac{(82+1)(2 \times 82 + 1)}{6} = \frac{83 \times 165}{6}\\ \ \\Average = \frac{83 \times 55}{2} = \frac{4565}{2} = 2282.5$$​​
So the correct answer is (d)