The average of three numbers A,B, and C is 48 . The average of A and B is 45 . The average of B and C is 49 . What is the value of B ?

Correct option is B

Given
Average of A, B, and C = 48
Average of A and B = 45
Average of B and C = 49

Formula Used
Sum of numbers = Average$$\times$$​Count of numbers

Solution
Sum of A, B, and C:
$$A + B + C = 48 \times 3$$​ = 144 (Equation 1)
Sum of A and B:
$$A + B = 45 \times 2$$​ = 90 (Equation 2)
Sum of B and C:
$$B + C = 49 \times 2$$​= 98 (Equation 3)
Add Equation 2 and Equation 3:
(A + B) + (B + C) = 90 + 98
A + 2B + C = 188
Now, subtract Equation 1 from this result to find B:
(A + 2B + C) - (A + B + C) = 188 - 144
B = 44

Final Answer
So the correct answer is (b)