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    Average age of a group of 16 boys is 24 years. Two boys with ages 19 years and 18 years left the group. One boy with age 43 years joined the group. Wh
    Question

    Average age of a group of 16 boys is 24 years. Two boys with ages 19 years and 18 years left the group. One boy with age 43 years joined the group. What is the new average age (in years) of the group?

    A.

    21

    B.

    31

    C.

    28

    D.

    26

    Correct option is D

    Given:
    Initial number of boys = 16
    Initial average age = 24 years
    Ages of boys who left = 19 years and 18 years
    Age of boy who joined = 43 years
    Formula Used:
    Sum of ages = Average × Number of boys
    New Average = New sum of agesNew number of boys\frac{New\ sum\ of\ ages}{New\ number\ of\ boys}​​
    Solution:
    Calculate the initial total sum of ages of the 16 boys.
    Initial sum = 16 × 24 = 384
    Subtract the ages of the two boys who left the group.
    Sum after two boys left = 384 - 19 - 18 = 347
    Add the age of the new boy who joined the group.
    New sum = 347 + 43 = 390
    Calculate the new number of boys in the group.
    New number of boys = 16 - 2 + 1 = 15
    Find the new average age.
    New average = 39015\frac{390}{15}​ = 26
    Final Answer
    So the correct answer is (d)

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