Average age of a group of 16 boys is 24 years. Two boys with ages 19 years and 18 years left the group. One boy with age 43 years joined the group. What is the new average age (in years) of the group?

Correct option is D

Given:
Initial number of boys = 16
Initial average age = 24 years
Ages of boys who left = 19 years and 18 years
Age of boy who joined = 43 years
Formula Used:
Sum of ages = Average × Number of boys
New Average = $$\frac{New\ sum\ of\ ages}{New\ number\ of\ boys}$$​​
Solution:
Calculate the initial total sum of ages of the 16 boys.
Initial sum = 16 × 24 = 384
Subtract the ages of the two boys who left the group.
Sum after two boys left = 384 - 19 - 18 = 347
Add the age of the new boy who joined the group.
New sum = 347 + 43 = 390
Calculate the new number of boys in the group.
New number of boys = 16 - 2 + 1 = 15
Find the new average age.
New average = $$\frac{390}{15}$$​ = 26
Final Answer
So the correct answer is (d)