The average (rounded off to two decimal place) of the squares of the first 84 natural numbers is

Correct option is B

Given:
Number of terms (n) = 84
Formula Used:
Sum of squares of first n natural numbers = $$\frac{n(n+1)(2n+1)}{6}$$​​
Average of squares = $$\frac{(n+1)(2n+1)}{6}$$​​
Solution:
Substitute n = 84 into the average formula:
​$$\text{Average} = \frac{(84 + 1)(2 \times 84 + 1)}{6}\\ \ \\\text{Average}= \frac{85 \times 169}{6}\\ \ \\\text{Average}= \frac{14365}{6}\\ \ \\\text{Average} = 2394.166... \approx 2394.17$$​​
So the correct answer is (b)