The average of the squares of the first 83 natural numbers is

Correct option is C

Given:
n = 83
Formula Used:
Average of squares of first n natural numbers = $$\frac{(n+1)(2n+1)}{6}$$​​
Solution:
​$$\text{Average} = \frac{(83 + 1)(2 \times 83 + 1)}{6}\\ \ \\\text{Average} = \frac{84 \times 167}{6}\\ \ \\\text{Average} = 14 \times 167 = 2338$$​​
So the correct answer is (c).