Correct option is D
Average of first 4 bangles = 103 g
Total weight of first 4 bangles = 4 × 103 = 412 g
Average of the remaining 6 bangles = 113 g
Total weight of remaining 6 bangles = 6 × 113 = 678 g
Total weight of 10 bangles = 412 + 678 = 1090 g
Average weight of 10 bangles = 1090 ÷ 10 = 109 g
Formula Method:
Overall Average = (n₁a₁ + n₂a₂) / (n₁ + n₂)
= (4 × 103 + 6 × 113) / 10
= (412 + 678) / 10
= 1090 / 10
= 109 g