The average of first 116 even numbers is

Correct option is A

Given:

We need the average of the first 116 even numbers.

Formula Used:

First n even numbers are: 2$$, 4, 6, \dots, 2n.$$​​

Average of first n even numbers = $$\frac{\text{Sum of first n even numbers}}{n}.$$​​

Sum of first n even numbers = n (n + 1).
(since 2 + 4 +$$\dots + 2n = 2 \cdot \frac{n(n+1)}{2} = n(n+1)$$​)

Solution:

For n = 116:

Sum = 116 × 117 = 13572

Average = $$\frac{13572}{116} =$$​ 117

The average of the first 116 even numbers = 117