The area of a triangle whose sides are of lengths 5 cm, 6 cm and 8 cm is:

Correct option is D

Given:

Sides of a triangle are 5cm,6cm and 8cm

Formula Used:

Area of triangle = $$\sqrt{s(s-a)(s-b)(s-c)}$$​​

​$$s= \frac{a+b+c}{2}$$​​

Where s is semi perimeter and a, b, c are sides of triangle

Solution:

We have sides as 5cm,6cm and 8cm

​$$s= \frac{a+b+c}{2} = \frac{5+6+8}{2} = 9.5cm$$​​

Area = $$\sqrt {9.5(9.5-5)(9.5-6)(9.5-8)}$$​​

​$$= \sqrt {9.5(4.5)(3.5)(1.5)}$$​​

​$$= \sqrt {224.4375}$$​​

= 14.98 cm²