Ten resistors having the same value of resistance i.e. 10 ohm, are connected in parallel. What will be the equivalent resistance of this connection?

Correct option is A

​$$\textbf{Concept:} \\[4pt]\text{When 'n' resistances are connected in series, the value of } R_{eq} \text{ is given by:} \\[4pt]R_{eq} = R_1 + R_2 + \dots + R_n \\[6pt]\text{When 'n' identical resistances are connected in series, the value of } R_{eq} \text{ is given by:} \\[4pt]R_{eq} = nR \\[6pt]\text{When 'n' resistors are connected in parallel, the value of } R_{eq} \text{ is given by:} \\[4pt]\dfrac{1}{R_{eq}} = \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dots + \dfrac{1}{R_n} \\[6pt]\text{When 'n' identical resistances are connected in parallel, the value of } R_{eq} \text{ is given by:} \\[4pt]R_{eq} = \dfrac{R}{n} \\[10pt]\text{Given:} \\[4pt]\bullet \text{Resistance of each resistor } R_1 = 10\,\Omega \\[4pt]\bullet \text{Number of resistors } n = 10 \\[8pt]\text{For } n \text{ identical resistors connected in parallel, the equivalent resistance } R_{eq} \text{ is given by:} \\[4pt]\dfrac{1}{R_{eq}} = \dfrac{1}{R_1} + \dfrac{1}{R_2} + \dots + \dfrac{1}{R_n} \\[6pt]\text{For } n \text{ identical resistors, this simplifies to:} \\[4pt]R_{eq} = \dfrac{R}{n} \\[8pt]\textbf{Solution:} \\[4pt]R_{eq} = \dfrac{10}{10} = 1\,\Omega$$​​