Seven men can complete a work in 12 days. They start the work and after 5 days, 3 men leave. In how many days will the remaining work be completed by the remaining men?
Given:
7 worker complete the work in 12 days
After 5 days, 3 worker left
Formula used:
M1D1 = M2D2
Solution:
According to the formula,
=> 7 12 = 7 5 + (7 - 3)D
=> 84 = 35 + 4D
=> 4D = 84 - 35 = 49
=> D = = 12
Thus, the correct answer is (b).
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