Correct option is D
Solution:
Let efficiency of Q be 2 unit/da
=> Efficiency of P = 2/2 = 1 unit unit/day
=> Efficiency of R = (2 + 1)/2 = 1.5 unit/day
Total work = 1.5 × 40 = 60 units
∴ P, Q and R together can complete the whole work in = 60/(2 + 1 + 1.5) = 60/4.5 = 40/3 days