Correct option is D
Let the total work = LCM of 18 and 15 = 90
Efficiency of P = 90/18 = 5 unit/day
Efficiency of P + Q = 120/15 = 6 unit/day
The work done by P and Q in 10 days = 6×10= 60 unit
Remaining work = 90 – 60 = 30 unit
Remaining work done by P = 30/ 5= 6 days .