Correct option is C
Given:
Mohan is twice as efficient as Kamlesh.
Together, they complete the task in 22 days.
Concept Used:
Total Work=Efficiency×Time
Solution:
Let Kamlesh’s efficiency = 1 unit/day.
Mohan’s efficiency = 2 units/day (twice as efficient).
Total Efficiency = 2 ( Mohan ) + 1 ( Kamlesh ) = 3 units/day
Total Work=Efficiency×Time=3×22=66 units
TimeMohan=Mohan’s EfficiencyTotal Work=266=33 days
Alternate Method :
Let Mohan’s time alone = m days.
Kamlesh’s time alone = 2m days (since Mohan is twice as efficient).
m1+2m1=221 2m3=221 2m=66
m = 33 days