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    Mohan is twice as good as Kamlesh and together, they finish a task in 22 days. Mohan alone can finish the task in:
    Question

    Mohan is twice as good as Kamlesh and together, they finish a task in 22 days. Mohan alone can finish the task in:

    A.

    35 days

    B.

    31 days

    C.

    33 days

    D.

    37 days

    Correct option is C

    Given:
    Mohan is twice as efficient as Kamlesh.
    Together, they complete the task in 22 days.
    Concept Used:
    Total Work=Efficiency×Time\text{Total Work} = \text{Efficiency} \times \text{Time}
    Solution:
    Let Kamlesh’s efficiency = 1 unit/day.
    Mohan’s efficiency = 2 units/day (twice as efficient).
    Total Efficiency = 2 ( Mohan ) + 1 ( Kamlesh ) = 3 units/day
    Total Work=Efficiency×Time=3×22=66 units\text{Total Work} = \text{Efficiency} \times \text{Time} = 3 \times 22 = 66 \text{ units}​​
    TimeMohan=Total WorkMohan’s Efficiency=662=33 days\text{Time}_{\text{Mohan}} = \frac{\text{Total Work}}{\text{Mohan’s Efficiency}} = \frac{66}{2} = 33 \text{ days}​​

    Alternate Method :
    Let Mohan’s time alone = m days.
    Kamlesh’s time alone = 2m days (since Mohan is twice as efficient).

    1m+12m=122 32m=122 2m=66\frac{1}{m} + \frac{1}{2m} = \frac{1}{22} \\ \ \\\frac{3}{2m} = \frac{1}{22}\\ \ \\2m = 66

    m = 33 days

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