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If Mohit, Nitu and Soma can complete a piece of work in 5 days, 6 days and 8 days, respectively, then in how many days will the work be completed if t
Question

If Mohit, Nitu and Soma can complete a piece of work in 5 days, 6 days and 8 days, respectively, then in how many days will the work be completed if they work on alternate days starting with Mohit on first day, then Nitu on second day. then Soma on third day, then Mohit on fourth day and so on.

A.

57125\frac{7}{12}​​

B.

71607\frac{1}{60}​​

C.

47154\frac{7}{15}​​

D.

61126\frac{1}{12}​​

Correct option is D

Given:
Mohit can complete the work in 5 days.
Nitu can complete the work in 6 days.
Soma can complete the work in 8 days.
They work on alternate days starting with Mohit, then Nitu, then Soma, repeating the cycle.
Formula Used: 
Total Work = Efficiency ×\times Time
Solution: 
Total Work = LCM of 5, 6 and 8 = 120 unit

Efficiency of Mohit = 1205=24 unit per day\frac{120}{5} = 24 \,unit\, per\, day

Efficiency of Nitin = 1206=20 unit per day\frac{120}{6} = 20 \,unit\, per\, day

Efficiency of Soma = 1208=15 unit per day\frac{120}{8} = 15 \,unit\, per\, day

3 day's work = 24 + 20 + 15 = 59 unit
in 6's day  = 2 × 59 = 118 unit
Remaining work done by Mohit in = 224\frac{2}{24} = 112\frac{1}{12}
Total Number of days = 6112\frac{1}{12} ​

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