Correct option is C
Given:
Time taken by A = 10 days
B is 25% more efficient than A
Required task to complete = 60%
Formula Used:
Efficiency of B = Efficiency of A × (1 + 100Percentage)
Time = Combined RateWork
Solution:
Let total work be 1 unit.
A's 1-day work (efficiency) = 101
Since B is 25% more efficient than A, B's efficiency is:
B's 1-day work = 101×(1+10025)
B's 1-day work = 101×1.25=101.25=1000125=81
Combined 1-day work of A and B:
Rate = 101+81
Rate = 404+405=409
We need to complete 60% of the task:
Work required = 10060=53
Time taken = 40953
Time taken = 53×940
Time taken = 45120=38=232 days
Final Answer
So the correct answer is (c)
Exam Hall Method: