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A, B and C can individually do a piece of work in 2 days each. How long (in days) will they take to do thrice the same work, working together?
Question

A, B and C can individually do a piece of work in 2 days each. How long (in days) will they take to do thrice the same work, working together?

A.

4

B.

3

C.

6

D.

2

Correct option is D

Given:
Time taken by A individually = 2 days
Time taken by B individually = 2 days
Time taken by C individually = 2 days
Formula Used:
Work done in 1 day = 1Total Days\frac{1}{\text{Total Days}}​​
Solution:
Work done by A in 1 day = 12 \frac{1}{2}​​

Work done by B in 1 day = 12 \frac{1}{2}

Work done by C in 1 day = 12 \frac{1}{2}​​
Total work done by A, B, and C together in 1 day = 12+12+12=32 \frac{1}{2} + \frac{1}{2} + \frac{1}{2} = \frac{3}{2}​​

Time taken to complete 1 unit of work = 23 \frac{2}{3}​ days
Time taken to complete thrice (3 times) the work = 3×23 3 × \frac{2}{3}​​
= 2  days
Final Answer
So the correct answer is (d) 

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