Correct option is D
Given:
A's time = 3 days
B's time = 12 days
C's time = 12 days
Target Work = Twice the original work
Formula Used:
Total Work = LCM of individual times
Time =
Solution:
Let the original total work be the LCM of 3, 12, and 12, which is 12 units.
Efficiency of A = = 4 units/day
Efficiency of B = = 1 unit/day
Efficiency of C = = 1 unit/day
Combined efficiency = 4 + 1 + 1 = 6 units/day
Target work is twice the original = 2 × 12 = 24 units.
Time required = = 4 days
Final Answer
So the correct answer is (d)