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If A can complete a task in 10 days and B is 25% more efficient than A, how long (in days) will it take them to complete 60% of the task when they wor
Question

If A can complete a task in 10 days and B is 25% more efficient than A, how long (in days) will it take them to complete 60% of the task when they work together?

A.

2 1/3

B.

1 2/3

C.

2 2/3

D.

1 1/3

Correct option is C

Given:
Time taken by A = 10 days
B is 25% more efficient than A
Target work = 60%
Formula Used:
Work = Efficiency × Time
Solution:
Let the efficiency of A be 100%
Efficiency of B = 100% + 25% = 125%
Ratio of efficiency of A and B = 100 : 125 = 4 : 5
Total Work = 4 × 10 = 40
Target Work = 40 × 60100\frac{60}{100}​ = 24
Combined efficiency of A and B = 4 + 5 = 9
Time required = 249=83=223 \frac{24}{9} = \frac{8}{3} = 2 \frac{2}{3}​​
Final Answer
So the correct answer is (c)

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