Find the area of a triangle, whose sides are 0.24 m, 28 cm and 32 cm.

Correct option is A

Given:

Side 1 = 0.24 m = 24 cm

Side 2 = 28 cm

Side 3 = 32 cm

Formula Used: 

Heron's formula;

​$$s = \frac{a + b + c}{2}$$​​

Area of triangle = $$\sqrt{s(s - a)(s - b)(s - c)}$$​​

Solution:

a = 24cm, b = 28cm, c = 32cm

s =$$\frac{24 + 28 + 32}{2}$$​  = 42 cm

Area of triangle = $$\sqrt{42(42 - 24)(42 - 28)(42 - 32)}$$​​

​$$= \sqrt{42 \times 18 \times 14 \times 10}$$​​

​$$= 84\sqrt{15} \, \text{cm}^2$$​​