Find the area (in cm²) of a triangle whose length of each side is 7 cm, 24 cm and 0.25 m.

Correct option is A

Given:

Side 1 = 7 cm

Side 2 = 24 cm

Side 3 = 0.25 m = 25 cm (conversion from meters to centimeters)

Formula Used:

Semi-perimeter (s) = $$\frac{a + b + c}{2}$$​​

Using Heron’s Formula:

Area of triangle} = $$\sqrt{s(s - a)(s - b)(s - c)}$$​​

Solution:

Convert all sides to cm:

​$$a = 7 \text{ cm},\quad b = 24 \text{ cm},\quad c = 25 \text{ cm}$$​​

s = $$\frac{7 + 24 + 25}{2} = \frac{56}{2} = 28 \text{ cm}$$​​

Area of triangle = $$\sqrt{28(28 - 7)(28 - 24)(28 - 25)}$$​​

​$$= \sqrt{28 \times 21 \times 4 \times 3}$$​​

= $$\sqrt{7056}$$ = 84 cm²