Anil and Balbeer can finish a task in 3 days. They started working together, but after 2 days Anil got injured. Balbeer took 2 more days to finish the task. In how many days can Balbeer alone finish the same task?

Correct option is D

Given:
· Anil and Balbeer together can complete the task in 3 days.
· After 2 days of working together, Anil got injured, and Balbeer took 2 more days to finish the task.
Concept Used:
· We use the concept of work done per day by each person and calculate how much work is completed by each.
Solution:
1. Let the total work be 1 unit.
2. Anil and Balbeer together can finish the work in 3 days, so their combined 1-day work is 1/3.
3. In 2 days, they complete: 2 × 1/3 = 2/3 of the total work.
4. Remaining work = 1 - 2/3 = 1/3.
5. Balbeer alone completes the remaining 1/3 of the work in 2 days, so his 1-day work is: 1/3 ÷ 2 = 1/6.
6. If Balbeer’s 1-day work is 1/6, he can finish the entire task alone in: 1 ÷ 1/6 = 6 days.
Thus, Balbeer alone would take 6 days to finish the entire task.
Final Answer: (d) 6