An isosceles right-angled triangle has two equal sides of length 12 cm each. Find itsarea.

Correct option is A

Given:

An isosceles right-angled triangle with two equal sides of length 12 cm each.

Formula Used:

In an isosceles right-angled triangle, the two equal sides are the legs of the triangle, and the angle between them is 90°

The area of a right-angled triangle is given by:

Area of right-angled isosceles = $$\frac{1}{2} \times \text{Base} \times \text{Height}$$​​

Solution:

Area of right-angled isosceles:

​$$= \frac{1}{2} \times 12 \times 12$$​​

​$$= \frac{1}{2} \times 144$$​​

​$$= 72 \, \text{cm}^2$$​​

Thus, the area of the triangle is $$72 \, \text{cm}^2$$​​