A man has to cover a distance of 753 km in 12 hours. If he covers two-third of this distance in $$\frac{2}{3}$$​ of the time, then what should his speed (in km/hr) be to cover the remaining distance in the time left?​

Correct option is D

Given:
Total distance to be covered = 753 km
Total time available = 12 hours
Two-thirds of the distance is covered in two-thirds of the time.
Formula Used:
Speed = Distance / Time
Remaining distance = Total distance - Distance covered.
Solution:
Two-thirds of the distance = $$\frac{2}{3} \times 753 = 502 \, \text{km}$$​
Two-thirds of the time = $$\frac{2}{3} \times 12 = 8 \, \text{hours}$$​​
Speed = $$\frac{502}{8} = 62.75 \, \text{km/h}$$​​
Remaining distance = 753 - 502 = 251 km
Remaining time = 12 - 8 = 4 hours
Speed required to cover the remaining distance in the remaining time = $$\frac{251}{4} = 62.75 \, \text{km/h}$$​​