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A man has to cover a distance of 519 km in 7 hours. If he covers two-third of this distance in 5/7 of the time, then what should his speed (in km/hr)
Question

A man has to cover a distance of 519 km in 7 hours. If he covers two-third of this distance in 5/7 of the time, then what should his speed (in km/hr) be to cover the remaining distance in the time left?​

A.

86.5

B.

46.5

C.

66.5

D.

34.5

Correct option is A

Given:

Total distance = 519 km

Total time = 7 hours

Distance covered in the first part = 23\frac{2}{3}​ of 519 km

Time taken for the first part = 57 \frac{5}{7} of 7 hours

Formula Used:

Remaining distance = Total distance - Distance for first part

Remaining time = Total time - Time for first part

Speed required = Remaining distanceRemaining time\frac{\text{Remaining distance}}{\text{Remaining time}}​​

Solution:

Distance for the first part = 23×519\frac{2}{3} \times 519​ = 346 km

Time for the first part = 57×7\frac{5}{7} \times 7​ = 5 hours

Remaining distance = 519 - 346 = 173 km

Remaining time = 7 - 5 = 2 hours

Speed required = 1732\frac{173}{2}​ = 86.5 km/hr

Thus, the man should travel at a speed of 86.5 km/hr to cover the remaining distance in the time left.

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