Lokesh travels from City A to City B. If Lokesh drives his car at 3/4 of his normal speed, then he reaches City B 24 minutes late. Find the time (in minutes) that Lokesh would have taken to travel from City A to City B if he drove at his normal speed.

Correct option is C

Given:

Reduced speed = $$\frac{3}{4}$$​ of normal speed

Delay = 24 minutes

Concept Used:

When speed is reduced, time increases.

If speed becomes $$\frac{3}{4}$$​, then time becomes $$\frac{4}{3}$$​ times

Solution:

Let normal time taken = t minutes

Then new time = $$\frac{4}{3}t$$​  minutes

Difference in time = $$\frac{4}{3}t - t = \frac{1}{3}t$$​​

Now, 

​$$\frac{1}{3}t = 24 \\ \ \\ t = 24 \times 3 = 72$$​​

Time taken at normal speed = 72 minutes