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A man has to cover a distance of 150 km in 12 hours. If he covers two-third of this distance in 58\frac{5}{8}85​​of the time, then what should be
Question

A man has to cover a distance of 150 km in 12 hours. If he covers two-third of this distance in 58\frac{5}{8}of the time, then what should be his speed (in km/h, correct to one decimal place) to cover the remaining distance in the time left?

A.

11.1

B.

6.7

C.

10.5


D.

11.5

Correct option is A

Given:
Total distance = 150 km,

Time = 12 hrs.

Covered 23\frac{2}{3}​ distance in 58\frac{5}{8}​ time.

Formula Used:

Speed=DistanceTime\text{Speed} = \frac{\text{Distance}}{\text{Time}}​​

Solution: 

Covered23\frac{2}{3}​​ distance in58\frac{5}{8}​​ time.

So, 

Distance left=15023150=50 km\text{Distance left} = 150 - \frac{2}{3} \cdot 150 = 50 \, \text{km}​​

Time left=125812=4.5 hrs\text{Time left} = 12 - \frac{5}{8} \cdot 12 = 4.5 \, \text{hrs} 

Thus, Speed to cover the remaining distance;

Speed=504.511.1 km/h\text{Speed} = \frac{50}{4.5} \approx 11.1 \, \text{km/h}​​

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