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    A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches the base of a window 6 m above the gr
    Question

    A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches the base of a window 6 m above the ground. Find the length of the ladder.

    A.

    6.3 m

    B.

    7.5 m

    C.

    6.5 m

    D.

    7.8 m

    Correct option is C

    Given:

    Distance of foot of the ladder from the wall = 2.5 m

    Height of the window from the ground = 6 m

    We are to find the length of the ladder

    Concept Used:
    The ladder, wall, and ground form a right-angled triangle, with:

    Height = 6 m (vertical side)

    Base = 2.5 m (horizontal side)

    Hypotenuse = ladder length

    Formula Used:
    Using the Pythagoras Theorem:

    Ladder length2=(height)2+(base)2\text{Ladder length}^2 = (\text{height})^2 + (\text{base})^2​​

    Solution:

    Ladder length2=62+2.52=36+6.25=42.25\text{Ladder length}^2 = 6^2 + 2.5^2 = 36 + 6.25 = 42.25​​

    Ladder length = 42.25\sqrt{42.25}​ = 6.5 m

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