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A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches the base of a window 6 m above the gr
Question

A ladder is placed against a wall such that its foot is at a distance of 2.5 m from the wall and its top reaches the base of a window 6 m above the ground. Find the length of the ladder.

A.

6.3 m

B.

7.5 m

C.

6.5 m

D.

7.8 m

Correct option is C

Given:

Distance of foot of the ladder from the wall = 2.5 m

Height of the window from the ground = 6 m

We are to find the length of the ladder

Concept Used:
The ladder, wall, and ground form a right-angled triangle, with:

Height = 6 m (vertical side)

Base = 2.5 m (horizontal side)

Hypotenuse = ladder length

Formula Used:
Using the Pythagoras Theorem:

Ladder length2=(height)2+(base)2\text{Ladder length}^2 = (\text{height})^2 + (\text{base})^2​​

Solution:

Ladder length2=62+2.52=36+6.25=42.25\text{Ladder length}^2 = 6^2 + 2.5^2 = 36 + 6.25 = 42.25​​

Ladder length = 42.25\sqrt{42.25}​ = 6.5 m

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