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A is twice as efficient as B at completing a task, and together they can finish the task in 20 days. How many days would A alone take to complete the
Question

A is twice as efficient as B at completing a task, and together they can finish the task in 20 days. How many days would A alone take to complete the task?


A.

34

B.

30

C.

32

D.

28

Correct option is B

Given:
A is twice as efficient as B.
A and B together can complete the task in 20 days. 
Formula Used:
Total work = Efficiency ×\times Time
Solution:
Let the efficiency of A be 2x and B's efficiency be x unit per day
Total work = (2x+ x)×20\times 20 = 60x
Time taken by A to complete the work = 60x2x=30  days\frac{60x}{2x} =30\ \ days

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