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A can do a piece of work in 28 days. B is 68% more efficient than A. Find the number of days taken by B to do the same piece of work.
Question

A can do a piece of work in 28 days. B is 68% more efficient than A. Find the number of days taken by B to do the same piece of work.

A.

28/3 days

B.

15 days

C.

50/3 days

D.

25/2 days

Correct option is C

Given:
- A can complete the work in 28 days.
- B is 68% more efficient than A.

Formula Used:
- Efficiency and time are inversely proportional.

Solution:

Total Work = Efficiency of A ×\times  Time taken by A = 28× 1 = 28 unit
Efficiency of B = 168% of A = 168/100 = 1.68A.
Time taken by B =Total Work / Efficiency of B = 28 / 1.68 = 50/3 days

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