Given:
A can do a piece of work = 20 days
B can do a piece of work = 10 days
(A+B+C) can do the work in 5 days
Concept Used :
Let Pipe A can fill the tank in x hrs.
Pipe A can fill a tank in 1 hrs =
Solution :
A's 1 day's work =
B's 1 day's work =
(A+B+C)'s 1 day's work =
Let, C can complete the work in = x days
C's 1 day's work =
According to question,
∴ C alone can complete the work in 20 days.
English
80 Questions
160 Marks
60 Mins English English20 Questions40 Marks12 Mins English English80 Questions160 Marks60 Mins EnglishWorking together A, B and C can complete a certain work in 40 days. B and C together can complete thesame work in 60 days. B is 25% more efficient than A. In how many days will C alone complete 40% ofthe same work?
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