A can complete part of a work in 10 days. B is 5 times as efficient as A. In how many days will B alone complete the same work?
Given:
A can complete of work in 10 days; B is 5 times as efficient as A.
Formula Used:
Work done = Efficiency × Time.
Solution:
A's efficiency =
B's efficiency = 5 × A's efficiency =
Time taken by B =
Answer: (a) 2.5 days
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