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    A can complete  45\frac4554​​ part of a work in 10 days. B is 5 times as efficient as A. In how many days will B alone complete the same wor
    Question

    A can complete  45\frac45​ part of a work in 10 days. B is 5 times as efficient as A. In how many days will B alone complete the same work?

    A.

    2.5 days

    B.

    2 days

    C.

    1.5 days

    D.

    3 days

    Correct option is A

    Given:
    A can complete 45\frac 45​ of work in 10 days; B is 5 times as efficient as A.
    Formula Used:
    Work done = Efficiency × Time.
    Solution:
    A's efficiency =4510=450=225\frac{\frac{4}{5}}{10} = \frac{4}{50} = \frac{2}{25}​​
    B's efficiency = 5 × A's efficiency = 5×225=1025=255 \times \frac{2}{25} = \frac{10}{25} = \frac{2}{5}​​
    Time taken by B =125=52=2.5 days\frac{1}{\frac{2}{5}} = \frac{5}{2} = 2.5 \, \text{days}​​
    Answer: (a) 2.5 days

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