Correct option is D
Given:
- A and B together can complete the work in 54 days
- A and B work together for 12 days
- Remaining work is completed by A, B, and C in 28 days
- Work done by B in 6 days = C in 9 days
- We need to find how many days A alone will take to complete two-thirds of the work
Formula Used:
- Work = Rate × Time
- If person X completes work in D days, then
X's 1-day work = 1/D - To find remaining work:
Remaining Work = 1 − Work already done - Proportionality from “equal work” condition:
If B’s 6-day work = C’s 9-day work → 6B = 9C → relate efficiencies
Solution:
A + B’s 1-day work=541Work done in 12 days=12×541=92Remaining work=1−92=97A + B + C complete 97 of the work in 28 days=>Their 1-day work=97÷28=361Given: B’s 6-day work = C’s 9-day work=>6B=9C=>CB=23=>C=32BNow,A+B=541A+B+C=A+B+32B=A+35B=361Subtracting the two equations:(A+35B)−(A+B)=361−541 =>32B=1081=>B=721Substitute into A+B=541: A+721=541=>A=541−721 =2164−3=2161So, A’s 1-day work=2161Time to complete 32 of the work=32÷2161=32×216=144 days
Final Answer: (D) 144 days