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UPSSSC-JE’21 CE: Daily Practice Quiz. 10-November-2021

Know your strengths and practice your concepts with this quiz on UPSSSC-JE Recruitment 2021. This quiz for UPSSSC-JE Recruitment 2021 is designed specially according to UPSSSC-JE Syllabus 2021.

Quiz: Civil Engineering

Each question carries 1 mark
Negative marking: 1/4 mark
Time: 8 Minutes

Q1. For a linear elastic structural system, minimization of potential energy yields
(a) compatibility conditions
(b) constitutive relations
(c) equilibrium equations
(d) strain displacement relations

Q2. In a linear elastic structural element
(a) stiffness is directly proportional to flexibility
(b) stiffness is inversely proportional to flexibility
(c) Stiffness is equal to flexibility
(d) stiffness and flexibility are not related

Q3.The consistency index is greater than 1. the soil will behave as
(a) Liquid
(b) Plastic
(c) Solid
(d) None of these

Q4.For a sand having an internal friction of 300 the ratio of passive to active lateral earth pressure will be
(a) 1
(b) 3
(c) 6
(d) 9

Q5. Vane shear test is used for
(a) measuring the shearing strength of cohesive soil of low shear strength
(b) measuring the void ratio of sandy soils
(c) measuring the bearing capacity of soils
(d) None of these

Q6. The escape velocity on the earth is
(a) 1.0 km/sec
(b) 3.6 km/sec
(c) 8.8 km/sec
(d) 11.2 km/sec


S1. Ans.(a)
Sol. In linear elastic system
Potential energy (U)= ∫▒(M^2 dx)/2EI
→ Potential energy to be minimum
▭(∂U/∂P=0 )
→ This equation represents the compatibility condition at the point where P is acting.

S2. Ans.(b)
Sol. In linear elastic structure element
[∆]=[F] [ R]
[R]=[k] [∆]
so,▭([F]=1/[k] )
[F] → flexibility
[k] → stiffness

S3. Ans.(c)
Consistency index (I_C ) State
I_C>1            Solid or Semi-solid state
I_C<0            Liquid state
0 < I_C < 1    Plastic state


S4. Ans.(d)
Sol. Given, ϕ=30°
Active earth pressure coefficient k_a=(1-sinϕ)/(1+sinϕ)=(1-sin30)/(1+sin30)=0.5/1.5=1/3
〖Passive earth pressure coefficient k〗_P=(1+sinϕ)/(1-sinϕ)=(1+sin30)/(1-sin30)=1.5/0.5=3
k_P/k_a =3/(1\/3)
▭(k_P/k_a =9)

S5. Ans.(a)
Sol. Vane shear test is used for measuring the shearing strength of cohesive soil of low shear strength. It is suitable for sensitive clays.

S6. Ans.(d)
Sol. The escape velocity on the earth surface.
Ve = √(2g R_e ) , Re = 6.37 × 106 m
Ve = √(2×9.8×6.37× 10^6 )
Ve = 11.17 Km/sec

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