PSPCL-JE’21 EE: Daily Practices Quiz 05-Oct-2021

PSPCL RECRUITMENT 2021

Punjab State Power Corporation Ltd. (PSPCL), a power generating and distributing company of the Government of Punjab state, has released the notification for recruitment to the post of Clerk, Revenue Accountant, Junior Engineer (Electrical), Assistant Lineman & Assistant Sub Station Attendant Posts .
A total of 75 vacancies have been announced for the recruitment process of JE ELECTRICAL Engineering.
Exam Dates: 10 N0V-21 to 17 Nov-21

PSPCL-JE’21 EE: Daily Quiz

PSPCL-JE’21 EE: Daily Practices Quiz 05-Oct-2021

Each question carries 1 mark.
Negative marking: 1/4 mark
Total Questions: 06
Time: 08 min.

Q1. The condition for a maximum power output from dc motor is
(a) Eb=V
(b) Eb=V/2
(c) Eb=0
(d) Eb=V/√2

Q2. If the coefficient of coupling between two coils is increased, mutual inductance
between the coils
(a) Is decreased.
(b) Remains unchanged.
(c) Is increased.
(d) Changes depend on current only.

Q3. The brushes of a dc machine should be physically placed on the
(a) Armature in the polar axis.
(b) Armature in the interpolar axis.
(c) Commutator in the polar axis.
(d) Commutator in the interpolar axis.

Q4. A transformer is working at its full load and its efficiency is also maximum at which
iron los is 1000 watts. Then, its copper loss at half of full load will be:
(a) 250 watts
(b) 300 watts
(c) 400 watts
(d) 500 watts

Q5. A dynamometer type wattmeter responds to the
(a) Average value of active power
(b) Average value of reactive power
(c) Peak value of active power
(d) Peak value of reactive power

Q6. Which is the most severe fault?
(a) Phase to phase fault
(b) Phase to earth fault
(c) Three phases to ground fault
(d) Phase to phase to earth fault

SOLUTIONS

S1. Ans.(b)
Sol. Maximum power developed in a DC machine.
For motor: Eb=V/2
For generator: V=E/2

S2. Ans.(c)
Sol. Coefficient of coupling:
K=M/√(L1.L2 )
For constant L1 and L2 if K is increased then M increases since M α K if L_1 and L_2 are
constants.

S3. Ans.(b)
Sol. Brushes of a dc machine should be physically placed on the armature in the interpolar axis as shown below.

Sample Page - Part 351_2.1

S4. Ans.(a)
Sol. The iron loss fat full load is 1000 Watts and maximum efficiency is obtained at full
load.
So, x= √(Pi/Pcl )
∴ Full load copper loss = Ifl^2.R=1000 Watts
∴ Half load copper loss = (Ifl/2)^2×R
=1000/4=250 Watts

S5. Ans.(a)
Sol. A dynamometer gives average value of active power over a cycle.
P=Vrms Irms cosϕ

S6. Ans.(c)
Sol. LLLG or three – phase to ground fault is most severe and in this short-circuit current value is maximum.
Severity of fault:
LLLG > LLL > LLG > LL > LG

UPPSC-LECTURER’21 EE: Daily Practices Quiz 04-Oct-2021

UPPSC Technical Education Teaching Exam Notification 2021

Uttar Pradesh Public Service Commission has released the official notification for the recruitment of PrincipalLecturerLibrarian, and Workshop Superintendent. The Online application has been started on 15th September 2021 and the last date to apply online is 15th October 2021. The recruitment is for a total of 1370 UPPSC Polytechnic Lecturer Vacancies.

UPPSC-LECTURER’21 EE:  Daily Practices Quiz

UPPSC-LECTURER’21 EE: Daily Practices Quiz 04-Oct-2021

Each question carries 3 marks.
Negative marking: 1 mark each or 1/3rd
Total Questions: 06
Time: 08 min.

Q1. The time-constant of the network shown in the figure is
Sample Page - Part 351_3.1
(a) CR
(b) 2 CR
(c) CR/4
(d) CR/2

Q2. The signal is shown below in the figure represents?

Sample Page - Part 351_4.1

(a) Energy signal
(b) Power signal
(c) Energy & power
(d) Neither energy nor power

Q3. For induction motors at low values of slip:
(a) The torque slip is approximately a hyperbola
(b) The torque slip is approximately a straight line
(c) The torque slip curve is at its maximum
(d) The torque slip is approximately a parabola

Q4. The minimum number of two-input NAND gates required to perform the two-input
OR gate?
(a) 1
(b) 3
(c) 2
(d) 4

Q5. Phase reversed of 180⁰ as compared to input occurs in the output of
(a) CE amplifier
(b) CB amplifier
(c) CC amplifier
(d) All of the above

Q6. A single phase, half-wave, controlled rectifier has 400 sin⁡〖(314 t)〗 as the input voltage and R as the load. For a firing angle of 60⁰ for the SCR, the average output voltage is
(a) 200/π
(b) 240/ π
(c) 300/ π
(d) 400/ π

SOLUTIONS

Sample Page - Part 351_5.1

S2. Ans.(d)
Sol. This is ramp signal, ramp signal is neither energy signal nor power signal.

S3. Ans.(b)
Sol. For induction motor –
T=(KS E₂²R₂)/(R₂²+(S×_2)²)
at low value of slip, S×_2≪R₂
⇒ T=(KSE₂²R₂)/(R₂²)
⇒ T∝S

Sample Page - Part 351_6.1

S5. Ans.(a)
Sol. Phase reversed of 180⁰ as compared to input occurs in the output of CE amplifier.

S6. Ans.(c)
Sol. A single phase, half-wave, controlled rectifier, V_avg=V_m/2π(1+cos⁡〖α)〗
∵V_avg=400/2π(1+cos⁡〖60⁰)=(400×3)/(2π ×2)〗=300/π

Daily Concept Booster Electrical Engineering: HVDC Transmission Systems Part-02

Table of Contents

HVDC Transmission System Layout

The block diagram of the HVDC transmission system

Sample Page - Part 351_8.1

Filter

There are three types of filters used which are:
1. AC Filters:
These are passive circuits used to provide how impedance, shunt paths for AC harmonic currents. Both tuned and damped filter arrangements are used.
2. DC Filters:
These are similar to AC filters and are used for the filtering of DC harmonics.
3. High Frequency (RF/PLC) Filters:
These are connected between the converter transformer and the station AC bus to suppress any high-frequency currents. Sometimes such filters are provided on high-voltage DC bus connected between the DC filter and DC line and also on the neutral side.

Daily Concept Booster Civil Engineering : POISSON’S RATIO

            Poisson’s ratio (μ)

for homogeneous & Isotropic material elongation/contraction produced by any axial force in the direction of force is accompanied by contraction relongation in all transverse direction.
μ=[(lateral strain)/(Longitudental strain)]
Limit
(o≤μ≤0.5)

O → Cork
-1.5 → Rheotropic material (human tissue)

 

Poisson’s ratio Material
0.02-0.03

0.1-0.2

0.2-0.3

0.27-0.30

0.3

0.33

0.33-0.36

0.34

0.40

0.45-0.50

Glass

Concrete

Cast iron

Steel

Wrought iron

Aluminum

Copper

Brass & Bronze

Nylon

Rubber

 

→ if perfectly plastic material by applying load strain perpendicular to applied load direction is very less (approx. zero) so Poisson’s ratio has zero magnitude.
→ Ideal plastic
(μ=(-ϵy)/ϵx=0 )

 

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UPSSSC-JE’21 CE: Daily Practice Quiz. 04-October-2021

Know your strengths and practice your concepts with this quiz on UPSSSC-JE Recruitment 2021. This quiz for UPSSSC-JE Recruitment 2021 is designed specially according to UPSSSC-JE Syllabus 2021.

Quiz: Civil Engineering

Exam: UPSSSC-JE

Topic: Estimation and Valuation

Each question carries 1 mark

Negative marking: 1/4 mark

Time: 8 Minutes

Q1. While submitting a tender, the contractor is required to deposit some amount with the department as a guarantee of the tender known as ________.

(a) Earnest money

(b) Bank guarantee

(c) Security deposit

(d) Caution money

Q2. For ten cubic meter of brick masonry, the number of modular brick needed is:

(a) 4500

(b) 5000

(c) 5500

(d) 6000

Q3. According to IS 1200, floor finishes shall be measured in

(a) running meter

(b) cubic meter

(c) square meter

(d) Thickness

Q4. According to IS 1200, the metal sheet roofing shall be described in terms of

(a) meter

(b) cubic meter

(c) square meter

(d) thickness

Q5. Based on the occupancy, buildings are classified into ________ groups

(a) 9

(b) 10

(c) 8

(d) 7

 

SOLUTION

 

S1. Ans.(a)

Sol. The contractor is required to deposit some amount with the department as a guarantee of the tender known as earnest money. It is about 2% of total cost of construction.

 

S2. Ans.(b)

Sol. In 1m³ of brick masonry, the no. of modular brick required = 500 bricks

Hence, in 10 m³ of brick work, the no. of modular brick needed = 10 × 500 = 5000 bricks.

S3. Ans.(c)

Sol. According to IS:1200, floor finishes shall be measured in m² and form work is also measured in m².

S4. Ans.(d)

Sol. According to IS:1200, the metal sheet roofing shall be described in terms of thickness.

S5. Ans.(a)

Sol. Based on occupancy, buildings are classified into 9 groups and these are residential, Assembly Institutional, Educational, Industrial, Hazardous, Storage, Business and Mercantile.

 

NHPC-JE’21 CE: Daily Practices Quiz. 05-Oct-2021

Know your strengths and practice your concepts with this quiz on NHPC JE Recruitment 2021. This quiz for NHPC JE Recruitment 2021 is designed specially according to NHPC Syllabus 2021.

Quiz: Civil Engineering
Exam: NHPC-JE
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/4 mark
Time: 8 Minutes

Q1. If the radial acceleration of transition curve is 30cm/sec², radius is 200m and the velocity is 14m/sec. the length of the transition curve is
(a) 46.0 m
(b) 46.5 m
(c) 45.0 m
(d) 45.5 m

Q2. As per the working stress method of reinforced concrete design, if a concrete has permissible compressive stress of p, then the modular ratio is approximately given as:
(a) 93/p
(b) 140/p
(c) 210/p
(d) 280/p

Q3. When waste water is disposed of into a running stream, four zones are formed. In which of the following zones will the minimum level of dissolved oxygen be found?
(a) Zone of degradation
(b) Zone of active decomposition
(c) Zone of recovery
(d) Zone of clear water

Q4. Which one of the following defines Aridity index (AI)?
(a) AI=(PET-AET)/PET×100
(b) AI=PET/AET×100
(c) AI=AET/PET×100
(d) AI=(AET-PET)/AET×100
(where AET = Actual Evapotranspiration and PET = Potential Evapotranspiration)

Q5. A soil sample is having a specific gravity 2.60 and a void ratio of 0.78. The water content required to fully saturate, the soil at the void ratio would be
(a) 10%
(b) 30%
(c) 50%
(d) 70%

Q6. The maximum depth of neutral axis in a RC beam for Fe 415 grade of steel is:
(a) 0.53d
(b) 0.46d
(c) 0.67d
(d) 0.48d

Solutions

S1. Ans.(a)
Sol. C = 30 cm/sec²
= 0.30 m/sec²
R = 200 m.
V = 14 m/sec.
Length of transition curve (L) = V^3/(C.R)
= (14)^3/(0.3×200)
= 45.7 m.
= 46 m.

S2. Ans.(a)
Sol. modular ratio (m) =280/3σcbc
▭(σcbc=p)
M=280/3p
▭(m=93/p)

S3. Ans.(b)
Sol. There are four zones are formed when waste water is disposed off into a running stream
1. Zone of degradation
2. Zone of active decomposition
3. Zone of recovery
4. Zone of clear water
In zone of active decomposition water is more dark and more turbid and dissolved oxygen may go up to zero.

S4. Ans.(a)
Sol. ▭(Aridity Index (AI)=(PET-AET)/PET×100)
Where, AET = Actual Evapotranspiration
PET = Potential Evapotranspiration

S5. Ans.(b)
Sol.
Specific gravity (G)=2.60
Void ratio (e)=0.78
Water content (w)=?
Fully saturated i.e. S=1
se=wG
1×0.78=w×2.60
▭(w=30%)

S6. Ans.(d)
Sol.

Grade of steel Depth of neutral axis ()
Fe 250 0.53d
Fe 415 0.48d
Fe 500 0.46d

Where, d= effective depth

Daily Concept Booster Mechanical Engineering: Struts and Column

Struts and Column

The structural member which is subjected to axial compressive load is called strut.
The structure which is vertical and subjected to axial compressive load is called column

Buckling Failure

This failure is given by Euler’s and called Euler’s theory.
Euler’s theory is applicable for the long columns, and in this theory, the effect of crushing is neglected.
Let P_e= Buckling Load
E=Modulus of elasticity
I=Moment of inertia about the centroidal axis
l_e=Effective length

Sample Page - Part 351_11.1

Effective Length for the various end condition

END CONDITION EFFECTIVE LENGTH
Both End Hinged L
One Hinged and One Fixed L/√2
Both Ends Fixed L/2
One End Fixed and One End Free 2L

 

 

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UPPSC Lec’21 ME: Daily Practices Quiz. 05-Oct-2021

Quiz: Mechanical Engineering
Exam: UPPSC Lecturer
Topic: Miscellaneous

Each question carries 1 mark
Negative marking: 1/4 mark
Time: 6 Minutes

Q1. What is an azeotrope?
(a) A non-halogenic refrigerant
(b) A refrigerant dissolved in alcohol
(c) A mixture of refrigerants without phase separation
(d) An eco-friendly refrigerant

Q2. Air at 35°C DBT and 25°C dew point temperature passes through the water shower whose temperature is maintained at 20°C. What is the process involved?
(a) cooling and humidification
(b) sensible cooling
(c) cooling and dehumidification
(d) heating and humidification

Q3. For an air-conditioned space, RTH = 100 kW, RSHF = 0.75, volume flow rate = 100 m³/min, and indoor design specific humidity is 0.01 kg/kg of dry air. What is the specific humidity of the supply air?
(a) 0.010
(b) 0.0075
(c) 0.005
(d) 0.0025

Q4. In an air-standard Diesel cycle; r is the compression ratio, ρ is the fuel cut-off ratio and γ is the adiabatic index (C_p/C_V ). Its air standard efficiency is given by
(a) η=1-{1/(γ.r^(γ-1) ).((ρ^γ-1))/((ρ-1))}
(b) η=1-{1/(γ.r^(γ-1) ).((ρ^(γ-1)-1))/((ρ-1))}
(c) η=1-{1/(γ.r^(γ-1) ).((ρ^(γ-1) ))/((ρ-1))}
(d) η=1-{1/(γ.r^γ ).((ρ^(γ-1)-1))/((ρ-1))}

Q5. A Carnot engine receives 100 kJ of heat at 600 K. Heat is rejected at 300 K. The displacement volume is 0.2 m³. The mean effective pressure is
(a) 2 bar
(b) 2.5 bar
(c) 3 bar
(d) 3.5 bar

Q6. Piston compression rings are made of which one of the following?
(a) Cast iron
(b) Bronze
(c) Aluminium
(d) White metal

Solutions

S1. Ans.(c)
Sol. Azeotrope is a mixture of refrigerants without phase separation.

S2. Ans.(c)
Sol. As the temperature of water shower is less than dew point temperature hence, water vapour starts condensing. Thus, process involved is cooling and dehumidification.

S3. Ans.(c)
Sol.
RSHF=RSH/RTH
∴RSH=0.75×100=75 kW
RLH=100-75=25 kW
RLH = 50 cmm (w1 – w2)
W2 = 0.005 kg/kg of dry air

S4. Ans.(a)
Sol.
η_diesel=1-{1/r^(γ-1) (ρ^γ-1)/(γ(ρ-1)}
η of diesel engine increases as the load on the engine decreases and at limiting condition becomes to Otto. With increase in load, cut off ratio increases.

S5. Ans.(b)
Sol.
η=1-T_1/T_2 =1-300/600=0.5
W=ηQ_S=0.5×100=50 kJ
m.e.p. =W/V_s =50/0.2
= 250 kPa = 2.5 bar
Option (b) is correct

S6. Ans.(a)
Sol. Since grey cast iron has properties of self-lubrication and damping of small vibrations they are widely used for machine base, engine frames, drainage pipes, elevator and industrial furnace counter weights, pump housings cylinder and piston rings of IC engines, flywheel etc.

DFCCIL Answer Key 2021 OUT – Download DFFCIL Answer Key Now, Link to Raise Objection Activated

DFCCIL Answer Key 2021 out Download Now, Link to Raise Objection Activated. Dedicated Freight Corridor Corporation of India Limited has recently carried out the first stage examination for the recruitment of Junior Managers, Junior Executives, and Executives. The exam was carried from 27th September to 30th September 2021. The selected candidates will be allowed to appear for further DFCCIL Selection Process. In a recent notice, it is stated that DFCCIL Answer Key is to be released by DFCCIL Recruitment Board on the official website whose link will be active from 5/10/2021 10 hours 00 minutes to 9/10/2021 23 hours 55 minutes. DFCCIL Answer Key 2021 Download Direct link is given in the post below, check now.

DFCCIL Answer key 2021 Out : Link to Raise Objections | Check Details_50.1

DFCCIL Answer Key 202 Download

DFCCIL Answer key 2021 download link will get activated on the official website of DFCCIL from 5 October 2021 10 AM onwards, candidates are advised to check and download the same from the link given below.

DFCCIL Answer Key Download Link

DFCCIL Answer Key 2021, Link to Raise Objection

The Link to raise objection is also activated on the official website of DFCCIL along with the DFCCIL Answer Key, candidates who are facing issues related to the given answers by the DFCCIL board can raise objections for the same through the link given below.

DFCCIL Answer Key

DFCCIL Cutoff 2021

The DFCCIL Cutoff for Junior Managers, Junior Executives, and Executive examinations for different engineering and non-engineering branches will be out soon on the official website of DFCCIL. Candidates are advised to keep themselves updated with adda247 Engineering jobs to know more about DFCCIL Expected Cutoff 2021 according to the DFCCIL Answer Key.

DFCCIL Exam Analysis 2021

Checkout the branch-wise DFCCIL Exam Analysis 2021 given below

DFCCIL Junior Executive Analysis 2021 Electrical Engineering

DFCCIL Executive Exam Analysis 2021 Civil Engineering

DFCCIL Executive Exam Analysis 2021 Electrical Engineering

Steps to Download DFCCIL Answer Key 2021

  • Visit the given link redirected to the official DFCCIL website.-> https://dfccil.com/Carrer/index?Id=1
  • Click on the link for the raise objection notice.
  • Log in to the portal with your user id and password.
  • Click on submit and your DFCCIL Answer Key is displayed on the screen.
  • Check your answers and make sure there are no discrepancies.
  • Representations in respect of the tentative DFCCIL Answer Key, if any, may be submitted online from 05.10.2021 (10: 00 AM) to 09.10.2021 (11:45 PM).

DFCCIL Answer Key 2021 FAQs

1. When is the DFCCIL Answer Key release Date?

The DFCCIL Answer Key release date is 5 October 2021

2. When will be the DFCCIL Result 2021 declared?

After the Release of the DFCCIL Answer Key, the result is expected to come in the month of October.

3. Can I download the answer key for DFCCIL Examination 2021?

Yes, one can download the DFCCIL Answer Key 2021.

4 Can I raise an objection to any answer of the DFCCIL Answer key  2021 if I see any issue?

Yes, the DFCCIL answer key 2021 can be challenged if the candidate sees any issue.

 

 

UPRVUNL JE Exam Date 2021, Direct Link to Download Admit Card

UPRVUNL JE Exam Date 2021, Check Direct Link to Download Admit Card. Uttar Pradesh Rajya Vidyut Utpadan Nigam Limited (UPRVUNL) a UP State-owned Government organization has recently released its Revised Official notification to recruit Junior Engineers from Electronics, Mechanical, Electrical, and Computer Science Branches. According to the latest update UPRVUNL JE Exam Date 2021 is released by the UPRVUNL Recruitment board. Along with it, a complete exam schedule is also given in the latest notification. Candidates can check the details of the UPRVUNL JE Exam Date and UPRVUNL JE Admit Card 2021 in the post below.

Preparing for UPRVUNL JE Recruitment 2021? Click Here to get Online Quick Revision Kit

UPRVUNL JE Exam Date 2021

 

Check UPRVUNL JE Syllabus 2021

UPRVUNL Recruitement 2021 Important Dates

Activity Dates
Short Notice Release Date 16th March 2021
Detailed Notification Release Date 20th March 2021
Online Application Start Date 3 June 2021 (10:00 am)
Last date to Apply Online 2 July 2021 (11:55 pm)
Last date to submit the application fee 4 July 2021 (11:45 pm)
UPRVUNL JE Exam Date 2021 21 October 2021 to 1 November 2021
UPRVUNL JE Admit Card 2021  5 October 2021

UPRVUNL JE Exam Date 2021

The Detailed UPRVUNL JE Exam Date 2021 and Schedule is out through on official website of UPRVUNL JE. All the details related to the UPRVUNL JE Exam Schedules such as exam dates, timings, and shifts are given in the table below.

POST Post

Code

Exam Date Exam Shift 

And Timing

Junior Engineer Electrical 1 21/10/2021 Shift I

(9 AM to 12 PM)

Shift II

(2:30 pm to 5:30 pm)

Junior Engineer Electrical 1 24/10/2021 Shift I

(9 AM to 12 PM)

Junior Engineer

Mechanical

2 24/10/2021 Shift II

(2:30 pm to 5:30 pm)

Junior Engineer

Mechanical

2 25/10/2021 Shift I

(9 AM to 12 PM)

Shift II

(2:30 pm to 5:30 pm)

Junior Engineer Electronics and Instrumentation 3 1/11/2021 Shift I

(9 AM to 12 PM)

 

Junior Engineer

Computer

4 1/11/2021 Shift II

(2:30 pm to 5:30 pm)

 

UPRVUNL JE Admit Card 2021

The UPRVUNL JE Admit 2021 is out on the official website of UPRVUNL JE, Candidates can also download the same from the link given below. Candidates are advised to read all the important details given in the admit card carefully, keep the required documents ready days well before examination and follow the covid-19 protocols as mentioned by the board.”To download call letters for documents verification for the post of Technician Grade-II (Electrician), (Post Code-11) against advt. no. U-37/UPRVUSA/2019 scheduled on 11/10/2021 & 12/10/2021″

UPRVUNL JE Admit Card Download DIRECT LINK

Related Links

UPRVUNL JE Syllabus 2021 UPRVUNL JE Previous Year Exam Analysis 
UPRVUNL JE Eligibility Criteria 2021 UPRVUNL JE Selection Process 2021
UPRVUNL JE Salary Allowances and Perks UPRVUNL JE Exam Date 2021