SSC CGL Dice Questions with Detailed Solutions

Given 

Formula Used
Rule of Dice: When two positions of the same dice have two common faces, the remaining third faces on both dice are opposite to each other.

Solution
In the given two positions:
Common faces are 3 and 5.
The remaining unshared faces are 6 in the first position and 1 in the second position.
Therefore, the face opposite to 6 is 1.

Final Answer
So the correct answer is (a)

Given

Logic:
In a row of four faces, opposite pairs are:
3 ↔ 1
4 ↔ 2
The remaining faces:
5 ↔ 6

Explanation:
Take 2 as the front face.
Then:
3 becomes the left face.
1 becomes the right face.
6 becomes the top face.
5 becomes the bottom face.
4 becomes the back face.
Hence, 3 and 1 are opposite faces.

Final Answer:
1

Final Correct Option:
A

Given:

Logic: The letter Z is common in both dices, we will write the letters starting from the common side in clockwise or anti clockwise direction.
1st Dice:  Z → W → U
2nd Dice: Z → Y → V
Hence,
Z   ↔  (Hidden side) in options
W  ↔  Y
U   ↔ V
Thus, the letter U is on the face opposite to V.
Thus, the correct option is (B) U.

Explanation:
Validate with given positions:
The first position has numbers 1, 8, and 3.
The second position has numbers 7, 5, and 3.
Face 3 is common for both positions, keep that face constant and moves in a clockwise direction, we get the faces opposite to each other.

From the above the opposite faces, we see 1 is opposite to 7 and 8 is opposite to 5.
Therefore, 3 will be on the face opposite to the face 6.
Hence, option (c) is correct.