arrow
arrow
arrow
​Which one of the following nucleic acids, with the same concentrations in water, will form a stable stem-loop structure upon annealing by heating and
Question

Which one of the following nucleic acids, with the same concentrations in water, will form a stable stem-loop structure upon annealing by heating and flash cooling on ice?

A.

​5’ – GGCUUAUUUUCUUCGG – 3’

B.

​5’ – CCGAACUUUUAUUCGG – 3’

C.

​5’ – AUGCCAUUUUCGGCUU – 3’

D.

5’ – AGAGCGUUUUAUUCGG – 3’

Correct option is B

A stem-loop structure (also called a hairpin loop) is a secondary structure that forms when a single-stranded nucleic acid folds back on itself, creating a complementary double-stranded stem region and an unpaired loop region.

Key factors influencing stem-loop stability include:

  1. Complementary Base Pairing: Strong base-pairing between regions forms a stable stem.
  2. GC Content: G≡C pairs form three hydrogen bonds, making them more stable than A=U pairs in RNA.
  3. Loop Length: Too short or too long loops reduce stability.
  • (a) 5’ – GGCUUAUUUUCUUCGG – 3’
    • The potential stem: GGCU.....UCGG
    • The loop is too long due to excess U’s, reducing stability.
  • (b) 5’ – CCGAACUUUUAUUCGG – 3’ (Correct Answer)
    • The potential stem: CCGA.....UCGG
    • A strong GC-rich stem with a balanced loop makes this structure stable.
  • (c) 5’ – AUGCCAUUUUCGGCUU – 3’
    • The potential stem: AUGCC.....CGCUU
    • The stem is less GC-rich, making it weaker compared to (b).
  • (d) 5’ – AGAGCGUUUUAUUCGG – 3’
    • The potential stem: AGAGC.....CGG
    • The loop is large, leading to an unstable structure.

Thus, option (b) forms the most stable stem-loop structure due to a well-balanced GC-rich stem and an optimal loop size.

Information Booster:

  • Stem-loop structures are critical in RNA folding, affecting stability and function.
  • RNA hairpins are found in tRNA, ribosomal RNA, and regulatory non-coding RNAs.
  • GC-rich stems contribute to high thermal stability due to three hydrogen bonds per pair.
  • Optimal loop size (4–10 nucleotides) enhances stability; very short or long loops destabilize the structure.
  • Flash cooling after heating helps stabilize the correct conformation by rapidly locking in base-pairing interactions.

Additional Knowledge:

(a) 5’ – GGCUUAUUUUCUUCGG – 3’

  • The presence of too many uracils (U’s) in the loop increases flexibility but reduces stem stability.
  • GGCU at the start can form a partial GC-paired stem, but the rest is weak.

(b) 5’ – CCGAACUUUUAUUCGG – 3’(Most Stable)

  • The stem (CCGA...UCGG) contains strong GC pairing, ensuring high stability.
  • The loop contains UUUUUAUU, which is an ideal size for stable formation.

(c) 5’ – AUGCCAUUUUCGGCUU – 3’

  • The stem contains AUGCC...GGCUU, but weaker AU pairs reduce stability.
  • Loop formation is possible but less stable than (b).

(d) 5’ – AGAGCGUUUUAUUCGG – 3’

  • The AGAGC...CGG stem is possible, but the loop is longer, making it unstable.
  • The presence of multiple purines (G, A) in the loop affects folding efficiency.

Similar Questions

test-prime-package

Access ‘CSIR NET Life Sciences’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
368k+ students have already unlocked exclusive benefits with Test Prime!
test-prime-package

Access ‘CSIR NET Life Sciences’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
368k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow