Correct option is C
Explanation-
Option A - MTT treatment of dividing cells followed by UVB irradiation – MTT is generally used to assess cell viability (via mitochondrial activity), not for lysing cells. However, UVB exposure after MTT incorporation might selectively damage dividing cells that have taken up the dye. This approach is unusual and less commonly used for lysis.
Option B - Treatment of dividing cells with Caspase inducers – These induce apoptosis and can affect both dividing and non-dividing cells, so not highly selective for newly dividing cells.
Option C - BrdU labelling of dividing cells followed by exposure to light – This is the correct answer. BrdU gets incorporated into the DNA of dividing cells. Upon exposure to UV light (especially UVA), it causes DNA strand breaks selectively in those cells, leading to lysis. This method is well-documented for selective killing of proliferating cells.
Option D - Treatment of dividing cells with ⁵¹Cr and measuring its release over time – This is used to measure cytotoxicity (by detecting 51Cr release) but not to cause selective lysis.
So, the correct answer is option C - BrdU labelling of dividing cells followed by exposure to light
