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Which of the following is not the Maxwell's equation?
Question

Which of the following is not the Maxwell's equation?

A.

divD=ρ\operatorname{div} \vec{D}=\rho​​

B.

divB=μ0 J\operatorname{div} \overrightarrow{\mathrm{B}}=-\mu_0 \overrightarrow{\mathrm{~J}}​​

C.

curlE=Bt\operatorname{curl} \overrightarrow{\mathrm{E}}=\frac{-\partial \overrightarrow{\mathrm{B}}}{\partial \mathrm{t}}​​

D.

curlH=J+Dt\operatorname{curl} \overrightarrow{\mathrm{H}}=\overrightarrow{\mathrm{J}}+\frac{\partial \overrightarrow{\mathrm{D}}}{\partial \mathrm{t}}​​

Correct option is B

Differential formIntegral formNameD=ρvSDdS=Vρv dVGauss’ law×H=J+DtSHdl=S(J+Dt)dSAmpere’s circuital lawB=0SBdS=0Gauss’ law of Magnetostatics (non-existence of magnetic monopole)×E=BtSEdl=ddtSBdSFaraday’s law of electromagnetic induction\begin{array}{|c|c|c|}\hline\textbf{Differential form} & \textbf{Integral form} & \textbf{Name} \\\hline\nabla \cdot \mathbf{D} = \rho_v & \int_S \mathbf{D} \cdot d\mathbf{S} = \int_V \rho_v \, dV & \text{Gauss' law} \\\hline\nabla \times \mathbf{H} = \mathbf{J} + \frac{\partial \mathbf{D}}{\partial t} & \oint_{\partial S} \mathbf{H} \cdot d\mathbf{l} = \int_S \left( \mathbf{J} + \frac{\partial \mathbf{D}}{\partial t} \right) \cdot d\mathbf{S} & \text{Ampere’s circuital law} \\\hline\nabla \cdot \mathbf{B} = 0 & \int_S \mathbf{B} \cdot d\mathbf{S} = 0 & \text{Gauss’ law of Magnetostatics (non-existence of magnetic monopole)} \\\hline\nabla \times \mathbf{E} = -\frac{\partial \mathbf{B}}{\partial t} & \oint_{\partial S} \mathbf{E} \cdot d\mathbf{l} = -\frac{d}{dt} \int_S \mathbf{B} \cdot d\mathbf{S} & \text{Faraday’s law of electromagnetic induction} \\\hline\end{array}​​

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