Two springs are connected to block of mass M placed on a frictionless surface as shown below. If both the springs have a spring constant $$k$$​. the frequency of oscillation of the block is:

Correct option is C

​$$\textbf{Given:}\\\begin{aligned}&\text{Block of mass } M \\&\text{Two springs connected in parallel, each with spring constant } k \\&\text{The frequency of oscillation is required.}\end{aligned}\\\textbf{Concept Used:}\\\begin{aligned}&\text{When two springs are connected in parallel, their effective spring constant is the sum of the individual spring constants:} \\&K_{\text{eq}} = k + k = 2k\end{aligned}$$​​$$\text{The frequency of oscillation } \omega \text{ for a mass-spring system is given by:} \\\omega = \sqrt{\frac{K_{eq}}{M}} = \sqrt{\frac{2k}{M}} \\\text{The frequency of oscillation is the natural frequency of the system, and it is inversely related to the square root of the mass and directly related to the spring constant.} \\\text{Using the formula for the frequency, we substitute } K_{eq} = 2k \text{ into the equation:} \\\omega = \sqrt{\frac{2k}{M}}$$​​